A polygon is a two-dimensional figure with three or more straight sides. (So triangles are actually a type of polygon.) Polygons are named according to the number of sides they have.
All polygons, no matter how many sides they possess, share certain characteristics:
The sum of the interior angles of a polygon with n sides is (n – 2). For instance, the sum of the interior angles of an octagon is (8 – 2) = 6 = .
The sum of the exterior angles of any polygon is .
The perimeter of a polygon is the sum of the lengths of its sides. The perimeter of the hexagon below is 5 + 4 + 3 + 8 + 6 + 9 = 35.
Regular Polygons
The polygon whose perimeter you just calculated was an irregular polygon. But most of the polygons on the SAT are regular: Their sides are of equal length and their angles congruent. Neither of these conditions can exist without the other. If the sides are all equal, the angles will all be congruent, and vice versa. In the diagram below, you’ll see, from lt to right, a regular pentagon, a regular octagon, and a square (also known as a regular quadrilateral):
Quadrilaterals
Good news: Most polygons on the SAT have just four sides. You won’t have to tangle with any dodecahedrons on the SAT you take. But this silver cloud actually has a dark lining: There are five different types of quadrilaterals that pop up on the test. These five quadrilaterals are trapezoids, parallelograms, rectangles, rhombuses, and squares.
Trapezoids
A trapezoid may sound like a new Star Wars character. Certainly, it would be less annoying than Jar Jar Binks. But it’s actually the name of a quadrilateral with one pair of parallel sides and one pair of nonparallel sides.
In this trapezoid, AB is parallel to CD (shown by the arrow marks), whereas AC and BD are not parallel.
The formula for the area of a trapezoid is
where s1 and s2 are the lengths of the parallel sides (also called the bases of the trapezoid), and h is the height. In a trapezoid, the height is the perpendicular distance from one base to the other.
To find the area of a trapezoid on the SAT, you’ll often have to use your knowledge of triangles. Try to find the area of the trapezoid pictured below:
The question tells you the length of the bases of this trapezoid, 6 and 10. But to find the area, you first need to find the height. To do that, split the trapezoid into a rectangle and a 45-45-90 triangle by drawing in the height.
Once, you’ve drawn in the height, you can split the base that’s equal to 10 into two parts: The base of the rectangle is 6, and the leg of the triangle is 4. Since the triangle is 45-45-90, the two legs must be equal. This leg, though, is also the height of the trapezoid. So the height of the trapezoid is 4. Now you can plug the numbers into the formula:
Parallelogram
A parallelogram is a quadrilateral whose opposite sides are parallel.
In a parallelogram,
Opposite sides are equal in length: BC = AD and AB = DC
Opposite angles are equal: and
Adjacent angles are supplementary:
The diagonals bisect (split) each other: BE = ED and AE = EC
One diagonal splits a parallelogram into two congruent triangles:
Two diagonals split a parallelogram into two pairs of congruent triangles: and
The area of a parallelogram is given by the formula
where b is the length of the base, and h is the height.
Rectangles
A rectangle is a quadrilateral in which the opposite sides are parallel and the interior angles are all right angles. Another way to look at rectangles is as parallelograms in which the angles are all right angles. As with parallelograms, the opposite sides of a rectangle are equal.
The formula for the area of a rectangle is
where b is the length of the base, and h is the height.
The diagonals of a rectangle are always equal to each other. And one diagonal through the rectangle cuts the rectangle into two equal right triangles. In the figure below, the diagonal BD cuts rectangle ABCD into congruent right triangles ABD and BCD.
Since the diagonal of the rectangle forms right triangles that include the diagonal and two sides of the rectangle, if you know two of these values, you can always calculate the third with the Pythagorean theorem. If you know the side lengths of the rectangle, you can calculate the diagonal. If you know the diagonal and one side length, you can calculate the other side. Also, keep in mind that the diagonal might cut the rectangle into a 30-60-90 triangle. That would make your calculating job even easier.
Rhombus
A rhombus is a specialized parallelogram in which all four sides are of equal length.
In a rhombus,
All four sides are equal: AD = DC = CB = BA
The diagonals bisect each other and form perpendicular lines (but note that the diagonals are not equal in length)
The diagonals bisect the vertex angles
The formula for the area of a rhombus is
where b is the length of the base and h is the height.
To find the area of a rhombus on the SAT (you guessed it), you’ll probably have to split it into triangles:
If ABCD is a rhombus, AC = 4, and ABD is an equilateral triangle, what is the area of the rhombus?
Since ABD is an equilateral triangle, the length of each side of the rhombus must be 4, and angles ADB and ABD are 60º. All you have to do is find the height of the rhombus. Draw an altitude from A to DC to create a 30-60-90 triangle.
Since the hypotenuse of the 30-60-90 triangle is 4, you can use the ratio 1::2 to calculate that the length of this altitude is 2. The area formula for a rhombus is bh, so the area of this rhombus is 4 2 = 8.
Square
A square combines the special features of the rectangle and rhombus: All its angles are 90º, and all four of its sides are equal in length.
The square has two more crucial special qualities. In a square,
Diagonals bisect each other at right angles and are equal in length.
Diagonals bisect the vertex angles to create 45º angles. (This means that one diagonal will cut the square into two 45-45-90 triangles, while two diagonals break the square into four 45-45-90 triangles.)
The formula for the area of a square is
where s is the length of a side of the square.
Because a diagonal drawn into the square forms two congruent 45-45-90 triangles, if you know the length of one side of the square, you can always calculate the length of the diagonal:
Since d is the hypotenuse of the 45-45-90 triangle that has legs of length 5, according to the ratio 1:1:, you know that .
Similarly, if you know the length of the diagonal, you can calculate the length of the sides of the square.
SAT数学常识讲解:多边形SAT数学常识讲解:多边形
A polygon is a two-dimensional figure with three or more straight sides. (So triangles are actually a type of polygon.) Polygons are named according to the number of sides they have.
All polygons, no matter how many sides they possess, share certain characteristics:
The sum of the interior angles of a polygon with n sides is (n – 2). For instance, the sum of the interior angles of an octagon is (8 – 2) = 6 = .
The sum of the exterior angles of any polygon is .
The perimeter of a polygon is the sum of the lengths of its sides. The perimeter of the hexagon below is 5 + 4 + 3 + 8 + 6 + 9 = 35.
Regular Polygons
The polygon whose perimeter you just calculated was an irregular polygon. But most of the polygons on the SAT are regular: Their sides are of equal length and their angles congruent. Neither of these conditions can exist without the other. If the sides are all equal, the angles will all be congruent, and vice versa. In the diagram below, you’ll see, from lt to right, a regular pentagon, a regular octagon, and a square (also known as a regular quadrilateral):
Quadrilaterals
Good news: Most polygons on the SAT have just four sides. You won’t have to tangle with any dodecahedrons on the SAT you take. But this silver cloud actually has a dark lining: There are five different types of quadrilaterals that pop up on the test. These five quadrilaterals are trapezoids, parallelograms, rectangles, rhombuses, and squares.
Trapezoids
A trapezoid may sound like a new Star Wars character. Certainly, it would be less annoying than Jar Jar Binks. But it’s actually the name of a quadrilateral with one pair of parallel sides and one pair of nonparallel sides.
In this trapezoid, AB is parallel to CD (shown by the arrow marks), whereas AC and BD are not parallel.
The formula for the area of a trapezoid is
where s1 and s2 are the lengths of the parallel sides (also called the bases of the trapezoid), and h is the height. In a trapezoid, the height is the perpendicular distance from one base to the other.
To find the area of a trapezoid on the SAT, you’ll often have to use your knowledge of triangles. Try to find the area of the trapezoid pictured below:
The question tells you the length of the bases of this trapezoid, 6 and 10. But to find the area, you first need to find the height. To do that, split the trapezoid into a rectangle and a 45-45-90 triangle by drawing in the height.
Once, you’ve drawn in the height, you can split the base that’s equal to 10 into two parts: The base of the rectangle is 6, and the leg of the triangle is 4. Since the triangle is 45-45-90, the two legs must be equal. This leg, though, is also the height of the trapezoid. So the height of the trapezoid is 4. Now you can plug the numbers into the formula:
Parallelogram
A parallelogram is a quadrilateral whose opposite sides are parallel.
In a parallelogram,
Opposite sides are equal in length: BC = AD and AB = DC
Opposite angles are equal: and
Adjacent angles are supplementary:
The diagonals bisect (split) each other: BE = ED and AE = EC
One diagonal splits a parallelogram into two congruent triangles:
Two diagonals split a parallelogram into two pairs of congruent triangles: and
The area of a parallelogram is given by the formula
where b is the length of the base, and h is the height.
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