SAT数学Problem Solving练习题三.

2017-08-06 作者: 209阅读

  • Question #1: In the x,y plane, which of the following statements are true?

    I. Line y + x = 5 is perpendicular to line y - x = 5. II. Lines y + x = 5 and y - x = 5 intersect each other on the y axis. III. Lines y + x = 5 and y - x = 5 intersect each other on the x axis.

    (a) I and III are both true.

    (b) I is the only true statement.

    (c) II is the only true statement.

    (d) I and II are both true.

    • Answer: y + x = 5 can be written as y = -x + 5. The slope of this equation is m1 = -1. y - x = 5 can be written as y = x + 5. The slope of this equation is m2 = 1. m2 = -1/m1 so the 2 lines are perpendicular. We also need to find where the 2 lines intersect. If we add the 2 equations, 2·y = 10, y = 5. From the first equation, x = 5 - y = 5 - 5 = 0. In conclusion the lines intersect at (0, 5) and this point is on the y axis. In conclusion I and II statements are correct.

  • Question #2: If a is an integer chosen randomly from the set {3, 5, 6, 9} and b is an integer chosen randomly from the set {2, 3, 4}, what is the probability that a/b is an integer?

    (a) .125

    (b) .250

    (c) .333

    (d) .5

    (e) .55

    • Answer: We have 4 possible integers for a and 3 for b, so the number of possible combinations for a/b is 4 · 3 = 12. a/b is an integer only for 4 combinations: 1. a = 3 and b = 3 2. a = 6 and b = 2 3. a = 6 and b = 3 4. a = 9 and b = 3 The probability that a/b is an integer is 4/12 = 1/3 = .333.

  • Question #3: What is the value of integer a, if x = 2 is a solution of the equation √(a + x) = 2·x?

    (a) a = 10

    (b) a = 12

    (c) a = 14

    (d) a = 16

    (e) a = 18

    • Answer: If we square the equation we get a + x = 4·x2 By replacing x with 2, a + 2 = 4·22, so a + 2 = 16. In conclusion, a = 14.

  • Question #4: What is the value of (3x + 1 - 3x) / (3x - 3x - 1)?

    (a) 6

    (b) 3x

    (c) 3x + 1

    (d) 3x - 1

    (e) 3

    • Answer: The numerator of the fraction is: 3x + 1 - 3x = 3x·(3 - 1) = 2 · 3x The denominator of the fraction is: 3x - 3x - 1 = 3x - 1·(3 - 1) = 2 · 3x - 1 We can write the fraction as (2 · 3x) / (2 · 3x - 1) = 3x / 3x - 1 = 3

  • Question #5: Two diameters of a circle create an angle AOB of 45o between them. What is the length of arc AB if the radius of the circle is 10/¶? (a) 5/2

    (b) 3/2

    (c) 2

    (d) 4

    (e) 6

    • Answer: The circumference of the circle is 2·¶·r = 2·¶·10/¶ = 20. The ratio between the length of arc AB and the circumference of the circle is equal between the ratio between the 45o angle and 360o. In conclusion, AB = 20 · 45o/360o = 20/8 = 5/2.

  • Question #6: A bus travels from town A to town B for 2 hours at a speed of 60 miles/hour. The bus stops in town B for 2 hours and then travels from town B to town C for 1 hour, at a speed of 50 miles/hour. What is the average speed of the bus?

    (a) 30miles/hour

    (b) 31miles/hour

    (c) 32miles/hour

    (d) 34miles/hour

    (e) 40miles/hour

    • Answer: The distance the bus travels from A to B is 60 miles/hour · 2 hours = 120 miles. Then, the bus travels from B to C: 50 miles/hour · 1 hour = 50 miles. The total distance traveled is 120 + 50 = 170 miles and the total time is 2 hours + 2 hours stop + 1 hour = 5 hours. In conclusion the average speed was 170 miles / 5 hours = 34 miles/hour.

  • Question #7: If a·b + b·c + c·a = 0, what is (a + b)2 + (b + c)2 + (c + a)2?

    (a) a2 + b2 + c2

    (b) 2·(a2 + b2 + c2)

    (c) (a2 + b2 + c2)/2

    (d) a2 + a + b2 + b + c2 +c

    (e) (a + b + c)/2

    • Answer: (a + b)2 + (b + c)2 + (c + a)2 = 2·(a2 + b2 + c2) + 2·(a·b + b·c + c·a) Since a·b + b·c + c·a = 0, the correct result is 2·(a2 + b2 + c2).

  • Question #8:

    Column A Column B
    x2 + 1 x + 1

    (a) The quantity in Column A is greater then the quantity in Column B.

    (b) The quantity in Column B is greater then the quantity in Column A.

    (c) The two quantities are equal.

    (d) The relationship cannot be determined from the information given.

    • Answer: We need to compare x2 + 1 with x + 1. This results in a comparison between x2 and x. For some x, x2 will be greater than x, e.g. for x = 2. For others, e.g. x = 1/2, x2 will be lower so the relationship cannot be determined from the information given.

  • Question #9: 2·m - n = 4

    m + 2·n = 12

    Column A Column B
    (m + n)2 61

    (a) The quantity in Column A is greater then the quantity in Column B.

    (b) The quantity in Column B is greater then the quantity in Column A.

    (c) The two quantities are equal.

    (d) The relationship cannot be determined from the information given.

    • Answer: From the first equation, n = 2·m - 4. Then, the first equation will be m + 2·(2·m - 4) = 12 m + 4·m - 8 = 12 so 5·m = 20 and m = 4 From the first equation, n = 2·m - 4 = 2·4 - 4 = 4 Column A expression will be (m + n)2 = (4 + 4)2 = (8)2 = 64 The quantity in Column A is greater than the quantity in Column B.

  • Question #7: If a and b are positive integers and a·b = 200, which of the following can be the sum a + b?

    (a) 40 (b) 46 (c) 33 (d) 55 (e) 50

    • Answer: 200 = 2·2·2·5·5. If a and b are positive integers, the 2 numbers and their sum can be: 2 + 100 = 102 4 + 50 = 54 5 + 40 = 45 8 + 25 = 33 10 + 20 = 30 (c) is the correct answer.

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